What is (\partial)/(\partial y)(ysin(xz)) ?

The answer to (\partial)/(\partial y)(ysin(xz)) is sin(xz)

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(\partial)/(\partial y)(ysin(xz))

\frac{\partial}{\partial y} (y sin (x z))

sin (x z)

Solution steps

\frac{\partial}{\partial y} (y sin (x z))

Treat

x, z

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= sin (x z) \frac{\partial}{\partial y} (y)

Apply the common derivative:

\frac{\partial}{\partial y} (y) = 1

= sin (x z) \cdot 1

Simplify

= sin (x z)

x^{2} y y^{^{'}} = e^{y}

y^{^{'}} = y^{2} - 3

y = x^{2} - 4 x, y = 2 x

\int \frac{1}{x 225 - x ^{2}} d x

\int - sin (x) cos^{7} (x) d x

What is (\partial)/(\partial y)(ysin(xz)) ?
The answer to (\partial)/(\partial y)(ysin(xz)) is sin(xz)