What is area 4x^2,x^4-6x^2,[-3,3] ?

The answer to area 4x^2,x^4-6x^2,[-3,3] is 414/5

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area 4x^2,x^4-6x^2,[-3,3]

area

4 x^{2}, x^{4} - 6 x^{2}, [- 3, 3]

\frac{414}{5}

Decimal Notation

82.8

Solution steps

Apply the area formula:

\int_{- 3}^{3} 4 x^{2} - (x^{4} - 6 x^{2}) d x

Solve

\int_{- 3}^{3} 4 x^{2} - (x^{4} - 6 x^{2}) d x : \frac{414}{5}

The area is:

= \frac{414}{5}

x \to 0 lim (\frac{sin ( π + x )}{x})

y = 12, y = 2 x^{2} - 11 x + 12

f (x) = 2 x^{7} - 3 x^{6} + 3 x^{3} - 4 x^{2} - 7

\frac{d}{d x} (ln (x^{2}) (3 x^{2} + 6))

\int_{2}^{5} (- 3 v + 4) d v

What is area 4x^2,x^4-6x^2,[-3,3] ?
The answer to area 4x^2,x^4-6x^2,[-3,3] is 414/5