What is the slope of y=x^2+x-1.0E-13 ?

The slope of y=x^2+x-1.0E-13 is 2x+1

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slope of y=x^2+x-1.0E-13

slope

y = x^{2} + x - 1.0 E - 13

2 x + 1

Solution steps

y = x^{2} + x - 1.0 E - 13

In order to find the slope of the function, take the derivative of

x^{2} + x - 1.0 E - 13

\frac{d}{d x} (x^{2} + x - 1.0 E - 13) = 2 x + 1

2 x + 1

\int \frac{1}{19 - x ^{2}} d x

3 t^{2} + 13 t

x \to 0 lim (\frac{( x ^{2} + 5 x )}{x})

y = \frac{3}{x ^{2} - 5}

\int \frac{2 y}{x + 1} d x