What is the tangent of f(x)=2sin(x),\at x= pi/4 ?

The tangent of f(x)=2sin(x),\at x= pi/4 is y=sqrt(2)x+sqrt(2)-pi/(2sqrt(2))

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tangent of f(x)=2sin(x),\at x= pi/4

tangent of

f (x) = 2 sin (x), at x = \frac{π}{4}

y = 2 x + 2 - \frac{π}{2 2}

Solution steps

Find the tangent point:

(\frac{π}{4}, 2)

Find the slope of

f (x) = 2 sin (x) : \frac{df ( x )}{d x} = 2 cos (x)

Compute the slope of

f (x) = 2 sin (x)

x = \frac{π}{4} : m = 2

Find the line with slope m=

2

and passing through

(\frac{π}{4}, 2) : y = 2 x + 2 - \frac{π}{2 2}

y = 2 x + 2 - \frac{π}{2 2}

(5.2) (- 9.6)

e^{x^{2} - x}

y = 3 + 4 x^{2} - 2 x^{3} x = a

x \to - \infty lim (- 3 x)

n = 1 \sum \infty \frac{10}{n}

What is the tangent of f(x)=2sin(x),\at x= pi/4 ?
The tangent of f(x)=2sin(x),\at x= pi/4 is y=sqrt(2)x+sqrt(2)-pi/(2sqrt(2))