What is (\partial)/(\partial y)(x^2*y^2) ?

The answer to (\partial)/(\partial y)(x^2*y^2) is 2x^2y

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(\partial)/(\partial y)(x^2*y^2)

\frac{\partial}{\partial y} (x^{2} \cdot y^{2})

2 x^{2} y

Solution steps

\frac{\partial}{\partial y} (x^{2} y^{2})

Treat

x

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= x^{2} \frac{\partial}{\partial y} (y^{2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= x^{2} \cdot 2 y^{2 - 1}

Simplify

= 2 x^{2} y

y^{^{''}} - 7 y^{^{'}} - 18 y = 0

x \to 2 lim (\frac{( x + 2 )}{3 x})

\frac{\partial}{\partial y} (y^{2} cos (x))

\frac{\partial}{\partial x} (6 tan (x y))

n = 1 \sum \infty sin (\frac{1}{2 ^{n}})

What is (\partial)/(\partial y)(x^2*y^2) ?
The answer to (\partial)/(\partial y)(x^2*y^2) is 2x^2y