What is the derivative of (-2x^3+2x^2^4) ?

The derivative of (-2x^3+2x^2^4) is 4(-2x^3+2x^2)^3(-6x^2+4x)

What is the first derivative of (-2x^3+2x^2^4) ?

The first derivative of (-2x^3+2x^2^4) is 4(-2x^3+2x^2)^3(-6x^2+4x)

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\frac{d}{d x} ((- 2 x^{3} + 2 x^{2})^{4})

4 (- 2 x^{3} + 2 x^{2})^{3} (- 6 x^{2} + 4 x)

Solution steps

\frac{d}{d x} ((- 2 x^{3} + 2 x^{2})^{4})

Apply the chain rule:

4 (- 2 x^{3} + 2 x^{2})^{3} \frac{d}{d x} (- 2 x^{3} + 2 x^{2})

= 4 (- 2 x^{3} + 2 x^{2})^{3} \frac{d}{d x} (- 2 x^{3} + 2 x^{2})

\frac{d}{d x} (- 2 x^{3} + 2 x^{2}) = - 6 x^{2} + 4 x

= 4 (- 2 x^{3} + 2 x^{2})^{3} (- 6 x^{2} + 4 x)

\frac{d}{d x} ((x + 2)^{- 1})

\frac{2 s + 3}{s ^{2} - 4 s + 20}

f (x) = x^{2} (1 - 2 x)

\frac{d y}{d x} = \frac{5 x}{y}

What is the derivative of (-2x^3+2x^2^4) ?
The derivative of (-2x^3+2x^2^4) is 4(-2x^3+2x^2)^3(-6x^2+4x)
What is the first derivative of (-2x^3+2x^2^4) ?
The first derivative of (-2x^3+2x^2^4) is 4(-2x^3+2x^2)^3(-6x^2+4x)