What is the limit as x approaches-0 of (6x)/(x^4) ?

The limit as x approaches-0 of (6x)/(x^4) is diverges

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limit as x approaches-0 of (6x)/(x^4)

x \to - 0 lim (\frac{6 x}{x ^{4}})

diverges

Solution steps

x \to - 0 lim (\frac{6 x}{x ^{4}})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 0 + lim (\frac{6 x}{x ^{4}}) = \infty

x \to - 0 - lim (\frac{6 x}{x ^{4}}) = - \infty

= diverges

\frac{- 4 e ^{(- s)} \cdot ( e ^{3} )}{( ( s - 3 ) ( s - 4 ) ( s + 1 ) )}

y^{^{'}} + y = e^{- 2 t}

\int_{6}^{8} \frac{20}{( x - 6 ) ^{3}} d x

\frac{d}{d x} (f (x) (e^{x}))

y^{^{'}} - 6 y^{^{'}} + 9 y = 0

What is the limit as x approaches-0 of (6x)/(x^4) ?
The limit as x approaches-0 of (6x)/(x^4) is diverges