What is the tangent of 4x-3x^2 ?

The tangent of 4x-3x^2 is y=(4-6a_{0})x+3a_{0}^2

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tangent of 4x-3x^2

tangent of

4 x - 3 x^{2}

y = (4 - 6 a_{0}) x + 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, 4 a_{0} - 3 a_{0}^{2})

Find the slope of

y = 4 x - 3 x^{2} : \frac{d y}{d x} = 4 - 6 x

Compute the slope of

y = 4 x - 3 x^{2}

x = a_{0} : m = 4 - 6 a_{0}

Find the line with slope m=

4 - 6 a_{0}

and passing through

(a_{0}, 4 a_{0} - 3 a_{0}^{2}) : y = (4 - 6 a_{0}) x + 3 a_{0}^{2}

y = (4 - 6 a_{0}) x + 3 a_{0}^{2}

- 30 t^{2} + 380 t, 7, 14

\int (5 - 15 x^{2}) csc^{2} (x^{3} - x) d x

\int e^{- θ} cos (6 θ) d θ

\frac{d}{d x} (e^{- x} (2 - x))

\frac{d}{d x} (39 e^{\frac{1}{x}})

What is the tangent of 4x-3x^2 ?
The tangent of 4x-3x^2 is y=(4-6a_{0})x+3a_{0}^2