tangent y=3x^3-2x,(1,1)

解答

切线

y = 3 x^{3} - 2 x, (1, 1)

y = 7 x - 6

求解步骤

计算

y = 3 x^{3} - 2 x

的斜率:

\frac{d y}{d x} = 9 x^{2} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 7

找到斜率 m=

7

且穿过

(1, 1)

的直线:

y = 7 x - 6

y = 7 x - 6

x \to 0 lim (ln (- x))

x \to \infty lim (arctan (\frac{x + 1}{x + 2}))

\frac{d y}{d x} - 2 x y = 6 x

x \to π lim (\frac{sin ( x )}{x})

\frac{d}{d x} (1 - sin (x))