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Beliebt Rechnen >

10y^'+20y=12

Lösung

10 y^{^{'}} + 20 y = 12

Lösung

y = - \frac{e ^{- 2 t - c_{1}}}{5} + \frac{3}{5}

Schritte zur Lösung

10 y^{'} (t) + 20 y = 12

Solve separable ODE:

y = - \frac{e ^{- 2 t - c_{1}}}{5} + \frac{3}{5}

y = - \frac{e ^{- 2 t - c_{1}}}{5} + \frac{3}{5}

Graph

Beliebte Beispiele

2(12)(18)+2(9)(dy)/(dt)=0

2 (12) (18) + 2 (9) \frac{d y}{d t} = 0

(dy)/(dt)=25t^4

\frac{d y}{d t} = 25 t^{4}

y^'=(6x-12)/(x^2),y(1)=20

y^{^{'}} = \frac{6 x - 12}{x ^{2}}, y (1) = 20

integral of 2xln(x^2)

\int 2 x ln (x^{2}) d x

integral of (cos^3(x))/(sin^2(x))

\int \frac{cos ^{3} ( x )}{sin ^{2} ( x )} d x