derivative y=5e^{5t+1}

解答

导数

y = 5 e^{5 t + 1}

25 e^{5 t + 1}

求解步骤

\frac{d}{d t} (5 e^{5 t + 1})

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= 5 \frac{d}{d t} (e^{5 t + 1})

使用连锁律:

e^{5 t + 1} \frac{d}{d t} (5 t + 1)

= e^{5 t + 1} \frac{d}{d t} (5 t + 1)

\frac{d}{d t} (5 t + 1) = 5

= 5 e^{5 t + 1} \cdot 5

化简

= 25 e^{5 t + 1}

\frac{d}{d x} (ln (cos (x)) + x)

\int \frac{x ^{2}}{( 9 x ^{2} - 4 ) ^{\frac{5}{2}}} d x

\int_{0}^{π} (5 e^{x} + 3 sin (x)) d x

\frac{\partial}{\partial x} (3 t sin^{2} (t))

d er i v a t i v e f (x) = 5 x - 1