What is the derivative of (x^4+3x^2-2)^5 ?

The derivative of (x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)

What is the first derivative of (x^4+3x^2-2)^5 ?

The first derivative of (x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)

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derivative of

(x^{4} + 3 x^{2} - 2)^{5}

5 (x^{4} + 3 x^{2} - 2)^{4} (4 x^{3} + 6 x)

Solution steps

\frac{d}{d x} ((x^{4} + 3 x^{2} - 2)^{5})

Apply the chain rule:

5 (x^{4} + 3 x^{2} - 2)^{4} \frac{d}{d x} (x^{4} + 3 x^{2} - 2)

= 5 (x^{4} + 3 x^{2} - 2)^{4} \frac{d}{d x} (x^{4} + 3 x^{2} - 2)

\frac{d}{d x} (x^{4} + 3 x^{2} - 2) = 4 x^{3} + 6 x

= 5 (x^{4} + 3 x^{2} - 2)^{4} (4 x^{3} + 6 x)

(x + 1) y^{^{'}} + (x + 2) y = 8 x e^{- x}

\int 8 x^{3} e^{x^{4}} d x

8 x sin (x)

1 - x^{2}, 13 - 7 x

\frac{\partial}{\partial x} (e^{8 x} cos (5 y))

What is the derivative of (x^4+3x^2-2)^5 ?
The derivative of (x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)
What is the first derivative of (x^4+3x^2-2)^5 ?
The first derivative of (x^4+3x^2-2)^5 is 5(x^4+3x^2-2)^4(4x^3+6x)