展开 4(2t-5)^2

解答

展开

4 (2 t - 5)^{2}

16 t^{2} - 80 t + 100

求解步骤

4 (2 t - 5)^{2}

展开

(2 t - 5)^{2} : 4 t^{2} - 20 t + 25

= 4 (4 t^{2} - 20 t + 25)

使用分配律:

m (a + b + c) = ma + mb + m c

4 (4 t^{2} - 20 t + 25) = 4 \cdot 4 t^{2} + 4 (- 20 t) + 4 \cdot 25

= 4 \cdot 4 t^{2} + 4 (- 20 t) + 4 \cdot 25

化简

4 \cdot 4 t^{2} + 4 (- 20 t) + 4 \cdot 25 : 16 t^{2} - 80 t + 100

= 16 t^{2} - 80 t + 100

\int x^{2} \cdot x^{2} - 9 d x

\frac{d P}{d t} = 0.5 (P) (1 - \frac{P}{1000})

\frac{d y}{d x} = \frac{3 sec ( y )}{( x + 1 ) ^{2}}

d er i v a t i v e f (x) = \frac{4 x}{( x ^{2} + 1 ) ^{2}}

n = 1 \sum \infty n (sin (nπ))