tangent 5x^2+xy+5y^2=11,(1,1)

解答

切线

5 x^{2} + x y + 5 y^{2} = 11, (1, 1)

y = - x + 2

求解步骤

计算

5 x^{2} + x y + 5 y^{2} = 11

的斜率:

\frac{d y}{d x} = \frac{- 10 x - y}{x + 10 y}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 1

找到斜率 m=

- 1

且穿过

(1, 1)

的直线:

y = - x + 2

y = - x + 2

\int - 4 + 9 s d s

\int 3 x^{2} e^{4 x} d x

\int \frac{( x + 1 )}{x x - 2} d x

\frac{\partial}{\partial x} (cos (x) - x cos (y) - y)

x \to - 2 - lim (2 - x)