What is the d/(dt)(e^{-t}-e^{-t}t) ?

The d/(dt)(e^{-t}-e^{-t}t) is e^{-t}t-2e^{-t}

What is the first d/(dt)(e^{-t}-e^{-t}t) ?

The first d/(dt)(e^{-t}-e^{-t}t) is e^{-t}t-2e^{-t}

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\frac{d}{d t} (e^{- t} - e^{- t} t)

e^{- t} t - 2 e^{- t}

Solution steps

\frac{d}{d t} (e^{- t} - e^{- t} t)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d t} (e^{- t}) - \frac{d}{d t} (e^{- t} t)

\frac{d}{d t} (e^{- t}) = - e^{- t}

\frac{d}{d t} (e^{- t} t) = - e^{- t} t + e^{- t}

= - e^{- t} - (- e^{- t} t + e^{- t})

Simplify

= e^{- t} t - 2 e^{- t}

f (x) = e^{x c o s (x)}

\frac{x}{x ^{2} - 8}

\int x - (\frac{1}{2})^{x} d x

x \to \infty lim (4^{x} - 1)

x \to 3 lim (\frac{( x ^{2} - 9 )}{2 x - 6})

What is the d/(dt)(e^{-t}-e^{-t}t) ?
The d/(dt)(e^{-t}-e^{-t}t) is e^{-t}t-2e^{-t}
What is the first d/(dt)(e^{-t}-e^{-t}t) ?
The first d/(dt)(e^{-t}-e^{-t}t) is e^{-t}t-2e^{-t}