What is the derivative of-32cos(8x) ?

The derivative of-32cos(8x) is 256sin(8x)

What is the first derivative of-32cos(8x) ?

The first derivative of-32cos(8x) is 256sin(8x)

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\frac{d}{d x} (- 32 cos (8 x))

256 sin (8 x)

Solution steps

\frac{d}{d x} (- 32 cos (8 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 32 \frac{d}{d x} (cos (8 x))

Apply the chain rule:

- sin (8 x) \frac{d}{d x} (8 x)

= - sin (8 x) \frac{d}{d x} (8 x)

\frac{d}{d x} (8 x) = 8

= - 32 (- sin (8 x) \cdot 8)

Simplify

= 256 sin (8 x)

\frac{d}{d x} (\frac{2 x + 9}{2 x})

f (x) = x^{2} + x - 2

\frac{d}{d x} (\frac{cos ( x )}{ln ( x )})

\int cos (x) a^{s i n (x)} d x

\frac{\partial}{\partial x} (\frac{x}{yz})

What is the derivative of-32cos(8x) ?
The derivative of-32cos(8x) is 256sin(8x)
What is the first derivative of-32cos(8x) ?
The first derivative of-32cos(8x) is 256sin(8x)