What is the derivative of (ln(x)/(9x)) ?

The derivative of (ln(x)/(9x)) is (1-ln(x))/(9x^2)

What is the first derivative of (ln(x)/(9x)) ?

The first derivative of (ln(x)/(9x)) is (1-ln(x))/(9x^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{d}{d x} (\frac{ln ( x )}{9 x})

\frac{1 - ln ( x )}{9 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{ln ( x )}{9 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{9} \frac{d}{d x} (\frac{ln ( x )}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{9} \cdot \frac{\frac{d}{d x} ( ln ( x ) ) x - \frac{d x}{d x} ln ( x )}{x ^{2}}

\frac{d}{d x} (ln (x)) = \frac{1}{x}

\frac{d x}{d x} = 1

= \frac{1}{9} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( x )}{x ^{2}}

Simplify

\frac{1}{9} \cdot \frac{\frac{1}{x} x - 1 \cdot ln ( x )}{x ^{2}} : \frac{1 - ln ( x )}{9 x ^{2}}

= \frac{1 - ln ( x )}{9 x ^{2}}

\int (\frac{1}{e ^{3 t}}) d t

x \to 0 lim (\frac{e - 1}{x})

\frac{d}{d x} (x^{4} - 3 x^{2} + 3)

x \to 1 lim (\frac{∣ 3 - x ∣}{3 - x})

\frac{d}{d x} (\frac{x ^{2}}{5 + x})

What is the derivative of (ln(x)/(9x)) ?
The derivative of (ln(x)/(9x)) is (1-ln(x))/(9x^2)
What is the first derivative of (ln(x)/(9x)) ?
The first derivative of (ln(x)/(9x)) is (1-ln(x))/(9x^2)