What is (\partial)/(\partial x)(rcos(t)sin(x)) ?

The answer to (\partial)/(\partial x)(rcos(t)sin(x)) is rcos(t)cos(x)

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(\partial)/(\partial x)(rcos(t)sin(x))

\frac{\partial}{\partial x} (r cos (t) sin (x))

r cos (t) cos (x)

Solution steps

\frac{\partial}{\partial x} (r cos (t) sin (x))

Treat

r, t

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= r cos (t) \frac{\partial}{\partial x} (sin (x))

Apply the common derivative:

\frac{\partial}{\partial x} (sin (x)) = cos (x)

= r cos (t) cos (x)

\int \frac{x}{( x + 3 )} d x

\frac{\partial}{\partial y} (4 x^{2} y)

f (x) = \frac{2}{( x - 1 ) ^{3}}

\int \frac{1}{x ( x + x )} d x

\int (3 x - 1) (x + 1) d x

What is (\partial)/(\partial x)(rcos(t)sin(x)) ?
The answer to (\partial)/(\partial x)(rcos(t)sin(x)) is rcos(t)cos(x)