What is the derivative of 3x^2+(8x/3-2) ?

The derivative of 3x^2+(8x/3-2) is 6x+8/3

What is the first derivative of 3x^2+(8x/3-2) ?

The first derivative of 3x^2+(8x/3-2) is 6x+8/3

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\frac{d}{d x} (3 x^{2} + \frac{8 x}{3} - 2)

6 x + \frac{8}{3}

Solution steps

\frac{d}{d x} (3 x^{2} + \frac{8 x}{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (\frac{8 x}{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (\frac{8 x}{3}) = \frac{8}{3}

\frac{d}{d x} (2) = 0

= 6 x + \frac{8}{3} - 0

Simplify

= 6 x + \frac{8}{3}

x \to 0 lim (- 5 (x - 3) ln (t (x) - 3))

\int ln (2 x) d x

\frac{\partial}{\partial x} (2 y \cdot e^{5 x^{2} - 9 y})

\int 11 x^{3} e^{x} d x

\int csc^{13} (x) d x

What is the derivative of 3x^2+(8x/3-2) ?
The derivative of 3x^2+(8x/3-2) is 6x+8/3
What is the first derivative of 3x^2+(8x/3-2) ?
The first derivative of 3x^2+(8x/3-2) is 6x+8/3