What is the integral of (4x^2+3x-7) ?

The integral of (4x^2+3x-7) is (4x^3)/3+(3x^2)/2-7x+C

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integral of (4x^2+3x-7)

\int (4 x^{2} + 3 x - 7) d x

\frac{4 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 7 x + C

Solution steps

\int 4 x^{2} + 3 x - 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 4 x^{2} d x + \int 3 x d x - \int 7 d x

\int 4 x^{2} d x = \frac{4 x ^{3}}{3}

\int 3 x d x = \frac{3 x ^{2}}{2}

\int 7 d x = 7 x

= \frac{4 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 7 x

Add a constant to the solution

= \frac{4 x ^{3}}{3} + \frac{3 x ^{2}}{2} - 7 x + C

\frac{d}{d x} (x^{2} y^{3} + x^{3} y^{2})

\int \frac{3 - 3 x}{1 - x} d x

\frac{\partial}{\partial x} (6 \cdot x \cdot y + 2 \cdot y)

\frac{d}{d x} ((x - 1)^{4})

\frac{d}{d x} (\frac{x}{x ^{2}})

What is the integral of (4x^2+3x-7) ?
The integral of (4x^2+3x-7) is (4x^3)/3+(3x^2)/2-7x+C