What is the slope ofintercept (4,5),(1,-3) ?

The slope ofintercept (4,5),(1,-3) is y= 8/3 x-17/3

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slope ofintercept (4,5),(1,-3)

slope intercept

(4, 5), (1, - 3)

y = \frac{8}{3} x - \frac{17}{3}

Solution steps

Compute the slope

(4, 5), (1, - 3) : m = \frac{8}{3}

Compute the

y

intercept:

b = - \frac{17}{3}

Construct the line equation

y = mx + b

where

m = \frac{8}{3}

and

b = - \frac{17}{3}

y = \frac{8}{3} x - \frac{17}{3}

t^{2} y^{^{''}} - 11 t y^{^{'}} + 35 y = 0

\int \frac{x ^{4} + 8}{x ^{3}} d x

y^{^{''}} + y = 2 csc^{2} (t)

\int_{0}^{c} 4 e^{2 x} d x

\int_{0}^{1} (e^{x} - x e^{x^{2}}) d x

What is the slope ofintercept (4,5),(1,-3) ?
The slope ofintercept (4,5),(1,-3) is y= 8/3 x-17/3