What is the solution for (dy)/(dx)=5y^2-y/x ?

The solution for (dy)/(dx)=5y^2-y/x is y= 1/(x(-5ln(x)+c_{1))}

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(dy)/(dx)=5y^2-y/x

\frac{d y}{d x} = 5 y^{2} - \frac{y}{x}

y = \frac{1}{x ( - 5 ln ( x ) + c _{1} )}

Solution steps

\frac{d y}{d x} = 5 y^{2} - \frac{y}{x}

Solve Bernoulli ODE:

y = \frac{1}{x ( - 5 ln ( x ) + c _{1} )}

y = \frac{1}{x ( - 5 ln ( x ) + c _{1} )}

y = x^{2} - 1 arcsec (x)

6 (t) e^{- 2 t}

\frac{\partial}{\partial x} ((1 + 2 x y^{2})^{3})

y = \frac{t}{( t - 5 ) ^{2}}

\int 5 cos^{3} (6 x) d x

What is the solution for (dy)/(dx)=5y^2-y/x ?
The solution for (dy)/(dx)=5y^2-y/x is y= 1/(x(-5ln(x)+c_{1))}