What is area 7cos(7x),7-7cos(7x) ?

The answer to area 7cos(7x),7-7cos(7x) is 2sqrt(3)+(4pi)/3

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area 7cos(7x),7-7cos(7x)

area

7 cos (7 x), 7 - 7 cos (7 x)

23 + \frac{4 π}{3}

Decimal Notation

7.65289 \dots

Solution steps

Apply the area formula:

\int_{\frac{π}{21}}^{\frac{5 π}{21}} ∣ 7 cos (7 x) - (7 - 7 cos (7 x)) ∣ d x

Solve

\int_{\frac{π}{21}}^{\frac{5 π}{21}} ∣ 7 cos (7 x) - (7 - 7 cos (7 x)) ∣ d x : 23 + \frac{4 π}{3}

The area is:

= 23 + \frac{4 π}{3}

\int sec^{9} (x) tan (x) d x

\frac{d}{d x} (sin (π \cdot x))

\frac{d}{d x} (\frac{7}{x + 8})

\frac{d}{d x} (A e^{- 3 x})

\int \frac{1}{ln ^{2} ( x )} d x

What is area 7cos(7x),7-7cos(7x) ?
The answer to area 7cos(7x),7-7cos(7x) is 2sqrt(3)+(4pi)/3