derivative of arcsin(2x-1)

Lösung

\frac{d}{d x} (arcsin (2 x - 1))

\frac{1}{x ( - x + 1 )}

Schritte zur Lösung

\frac{d}{d x} (arcsin (2 x - 1))

Wende die Kettenregel an:

\frac{1}{1 - ( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

= \frac{1}{1 - ( 2 x - 1 ) ^{2}} \frac{d}{d x} (2 x - 1)

\frac{d}{d x} (2 x - 1) = 2

= \frac{1}{1 - ( 2 x - 1 ) ^{2}} \cdot 2

Vereinfache

\frac{1}{1 - ( 2 x - 1 ) ^{2}} \cdot 2 : \frac{1}{x ( - x + 1 )}

= \frac{1}{x ( - x + 1 )}

y^{^{''}} - 2 y^{^{'}} - 3 y = 3 e^{2 t}, y (0) = 1, y^{^{'}} (0) = 0

x \to \infty lim (\frac{1}{3})

\frac{d y}{d x} + 2 y - 8 e^{- x} = 0, y (0) = 7

\int_{0}^{1} (e^{x}) - (x e^{x^{2}}) d x

\int \frac{1 + x ^{2}}{x - x ^{3}} d x