What is the derivative of 1.8^{2x} ?

The derivative of 1.8^{2x} is 1.17557…*3.24^x

What is the first derivative of 1.8^{2x} ?

The first derivative of 1.8^{2x} is 1.17557…*3.24^x

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derivative of

1. 8^{2 x}

1.17557 \dots \cdot 3.2 4^{x}

Solution steps

\frac{d}{d x} (1. 8^{2 x})

Simplify

1. 8^{2 x} : 3.2 4^{x}

= \frac{d}{d x} (3.2 4^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 3.2 4^{x} ln (3.24)

Refine to a decimal form

= 1.17557 \dots \cdot 3.2 4^{x}

\frac{( 2 s + 1 )}{s ^{2} + 2 s + 1}

y^{^{'}} = x^{2}

n = 1 \sum \infty \frac{5}{4 ^{n + 1}}

\frac{d}{d x} (cos (6 x^{3}))

(1 + y^{2}) d x + (1 + x^{2}) d y = 0

What is the derivative of 1.8^{2x} ?
The derivative of 1.8^{2x} is 1.17557…*3.24^x
What is the first derivative of 1.8^{2x} ?
The first derivative of 1.8^{2x} is 1.17557…*3.24^x