What is the integral of \sqrt[4]{x^3}+\sqrt[3]{x^4} ?

The integral of \sqrt[4]{x^3}+\sqrt[3]{x^4} is 4/7 x^{7/4}+3/7 x^{7/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of \sqrt[4]{x^3}+\sqrt[3]{x^4}

\frac{4}{7} x^{\frac{7}{4}} + \frac{3}{7} x^{\frac{7}{3}} + C

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{4}{7} x^{\frac{7}{4}} + \frac{3}{7} x^{\frac{7}{3}}

Add a constant to the solution

= \frac{4}{7} x^{\frac{7}{4}} + \frac{3}{7} x^{\frac{7}{3}} + C

\int (x + 6) d x

(x + 2)^{2} + (y - 3)^{2} = 37, (- 3, 9)

y = x^{2} + 9

y^{^{'}} + \frac{y}{t} = e^{t^{2}}

\frac{d ^{2} y}{d x ^{2}} - 2 \frac{d y}{d x} + y = \frac{e ^{x}}{1 + x ^{2}}

What is the integral of \sqrt[4]{x^3}+\sqrt[3]{x^4} ?
The integral of \sqrt[4]{x^3}+\sqrt[3]{x^4} is 4/7 x^{7/4}+3/7 x^{7/3}+C