What is (\partial)/(\partial x)(3x-y-1) ?

The answer to (\partial)/(\partial x)(3x-y-1) is 3

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(\partial)/(\partial x)(3x-y-1)

\frac{\partial}{\partial x} (3 x - y - 1)

3

Solution steps

\frac{\partial}{\partial x} (3 x - y - 1)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x) - \frac{\partial}{\partial x} (y) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (3 x) = 3

\frac{\partial}{\partial x} (y) = 0

\frac{\partial}{\partial x} (1) = 0

= 3 - 0 - 0

Simplify

= 3

\int \frac{1}{( x ^{2} + 5 )} d x

\int \frac{y}{x ^{2} y ^{2} + 1} d x

9 - x^{2}

3 x - 5

\frac{d}{d x} ([x + (x + sin^{2} (x))^{5}]^{4})

What is (\partial)/(\partial x)(3x-y-1) ?
The answer to (\partial)/(\partial x)(3x-y-1) is 3