(\partial)/(\partial x)(8x^2+y^2-9y)

解答

\frac{\partial}{\partial x} (8 x^{2} + y^{2} - 9 y)

16 x

求解步骤

\frac{\partial}{\partial x} (8 x^{2} + y^{2} - 9 y)

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (8 x^{2}) + \frac{\partial}{\partial x} (y^{2}) - \frac{\partial}{\partial x} (9 y)

\frac{\partial}{\partial x} (8 x^{2}) = 16 x

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (9 y) = 0

= 16 x + 0 - 0

化简

= 16 x

t an g e n t f (x) = x^{2} + 3 x + 1, at x = 4

x \to 0 lim (ln (0))

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