What is the derivative of (1+1/x) ?

The derivative of (1+1/x) is -2/(x^2)

What is the first derivative of (1+1/x) ?

The first derivative of (1+1/x) is -2/(x^2)

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\frac{d}{d x} (\frac{1 + 1}{x})

- \frac{2}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1 + 1}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (1 + 1) \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (1 + 1) \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (1 + 1) (- 1 \cdot x^{- 1 - 1})

Simplify

(1 + 1) (- 1 \cdot x^{- 1 - 1}) : - \frac{2}{x ^{2}}

= - \frac{2}{x ^{2}}

1 - x^{2}, ∣ x ∣

\int sin^{100} (x) cos^{3} (x) d x

\frac{\partial}{\partial x} (ln (x + 7 y + 9 z))

x \to 0 lim (\frac{2 x - sin ( x )}{x})

What is the derivative of (1+1/x) ?
The derivative of (1+1/x) is -2/(x^2)
What is the first derivative of (1+1/x) ?
The first derivative of (1+1/x) is -2/(x^2)