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tangent 8x^2-7x,\at 9

解答

切线

8 x^{2} - 7 x, at 9

解答

y = (16 a_{0} - 7) x - 8 a_{0}^{2}

求解步骤

计算在一般点

x = a_{0}

的切线

找到切点:

(a_{0}, 8 a_{0}^{2} - 7 a_{0})

计算

y = 8 x^{2} - 7 x

的斜率:

\frac{d y}{d x} = 16 x - 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 16 a_{0} - 7

找到斜率 m=

16 a_{0} - 7

且穿过

(a_{0}, 8 a_{0}^{2} - 7 a_{0})

的直线:

y = (16 a_{0} - 7) x - 8 a_{0}^{2}

y = (16 a_{0} - 7) x - 8 a_{0}^{2}

作图

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