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Popular >

y^'+4xy=0

Solution

y^{^{'}} + 4 x y = 0

Solution

y = e^{- 2 x^{2} + c_{1}}

Solution steps

y^{'} (x) + 4 x y = 0

Solve separable ODE:

y = e^{- 2 x^{2} + c_{1}}

y = e^{- 2 x^{2} + c_{1}}

Popular Examples

integral of 4(2x+5)^3

\int 4 (2 x + 5)^{3} d x

taylor sqrt(1-x^2),x=0 taylor

1 - x^{2}, x = 0

derivative of (x^2/(3+8x))

\frac{d}{d x} (\frac{x ^{2}}{3 + 8 x})

x \cdot y^{^{'}} + y^{2} = 0

integral of sqrt(5+4x-x^2)

\int 5 + 4 x - x^{2} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'+4xy=0 ?
The solution for y^'+4xy=0 is y=e^{-2x^2+c_{1}}