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Popular >

integral from 0 to 1 of (6x+1)

Solution

\int_{0}^{1} (6 x + 1) d x

Solution

4

Solution steps

\int_{0}^{1} 6 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 6 x d x + \int_{0}^{1} 1 d x

\int_{0}^{1} 6 x d x = 3

\int_{0}^{1} 1 d x = 1

= 3 + 1

Simplify

= 4

Popular Examples

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\int 3 x (cos (4 x)) d x

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\int cos (x^{4} + 2) d x

(dy)/(dx)= y/(10)(500-y)

\frac{d y}{d x} = \frac{y}{10} (500 - y)

(\partial)/(\partial x)(-sin(x^2y)*2xy)

\frac{\partial}{\partial x} (- sin (x^{2} y) \cdot 2 x y)

integral of x/(sqrt(1+4x^2))

\int \frac{x}{1 + 4 x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (6x+1) ?
The integral from 0 to 1 of (6x+1) is 4