integral from 0 to 2 of (x+y)

Lösung

\int_{0}^{2} (x + y) d y

2 x + 2

Schritte zur Lösung

\int_{0}^{2} x + y d y

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x d y + \int_{0}^{2} y d y

\int_{0}^{2} x d y = 2 x

\int_{0}^{2} y d y = 2

= 2 x + 2

t an g e n t \frac{1}{8 x}

\frac{d}{d x} (ln (e^{- 2 x} + cos (x)))

\int_{0}^{3} (\frac{x}{3} + 5) d x

\frac{d}{d x} (\frac{5 - x ^{2}}{5 + x ^{2}})

\frac{\partial}{\partial x} (\frac{1}{6} x^{3})