derivative f(x)=6e^x+2/(\sqrt[3]{x)}

Lösung

ableitung von

f (x) = 6 e^{x} + \frac{2}{3 x}

6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

Schritte zur Lösung

\frac{d}{d x} (6 e^{x} + \frac{2}{3 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (6 e^{x}) + \frac{d}{d x} (\frac{2}{3 x})

\frac{d}{d x} (6 e^{x}) = 6 e^{x}

\frac{d}{d x} (\frac{2}{3 x}) = - \frac{2}{3 x ^{\frac{4}{3}}}

= 6 e^{x} - \frac{2}{3 x ^{\frac{4}{3}}}

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