What is the tangent of f(x)=5-5x^2,(5,-120) ?

The tangent of f(x)=5-5x^2,(5,-120) is y=-50x+130

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of f(x)=5-5x^2,(5,-120)

tangent of

f (x) = 5 - 5 x^{2}, (5, - 120)

y = - 50 x + 130

Solution steps

Find the slope of

f (x) = 5 - 5 x^{2} : \frac{df ( x )}{d x} = - 10 x

Compute the slope of

f (x) = 5 - 5 x^{2}

(5, - 120) : m = - 50

Find the line with slope m=

- 50

and passing through

(5, - 120) : y = - 50 x + 130

y = - 50 x + 130

x \to 5 lim (x^{2} + 2 x - 4)

\int e^{13 x} d x

\frac{1}{2 s + 6}

\frac{d y}{d x} = π y + 12

\int \frac{e ^{5 x} - e ^{2 x} + 1}{e ^{x}} d x

What is the tangent of f(x)=5-5x^2,(5,-120) ?
The tangent of f(x)=5-5x^2,(5,-120) is y=-50x+130