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Frequently Asked Questions (FAQ)
What is the d/(dt)(\sqrt[3]{t}(t^2+4)) ?
- The d/(dt)(\sqrt[3]{t}(t^2+4)) is (t^2+4+6\sqrt[3]{t}t^{5/3})/(3t^{2/3)}
What is the first d/(dt)(\sqrt[3]{t}(t^2+4)) ?
- The first d/(dt)(\sqrt[3]{t}(t^2+4)) is (t^2+4+6\sqrt[3]{t}t^{5/3})/(3t^{2/3)}