What is laplacetransform t-2 ?

The answer to laplacetransform t-2 is 1/(s^2)-2/s

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laplacetransform t-2

laplace transform

t - 2

\frac{1}{s ^{2}} - \frac{2}{s}

Solution steps

L {t - 2}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {t} - L {2}

L {t} : \frac{1}{s ^{2}}

L {2} : \frac{2}{s}

= \frac{1}{s ^{2}} - \frac{2}{s}

y = lo g_{6} (x)

x \to 2 lim (x^{2})

\int \frac{1 + y}{y} d y

\int \frac{x - 1}{( x ^{2} + 4 x + 5 ) ( x + 1 )} d x

\frac{d y}{d x} + x^{2} y = 10 x^{2}

What is laplacetransform t-2 ?
The answer to laplacetransform t-2 is 1/(s^2)-2/s