derivative of x^2+y^4

Lösung

\frac{d}{d x} (x^{2} + y^{4})

2 x + 4 y^{3} \frac{d y}{d x}

Schritte zur Lösung

\frac{d}{d x} (x^{2} + y^{4})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (y^{4})

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (y^{4}) = 4 y^{3} \frac{d y}{d x}

= 2 x + 4 y^{3} \frac{d y}{d x}

t an g e n t f (x) = \frac{2 x - 1}{x + 7}, at x = 2

t an g e n t f (x) = \frac{1}{2 x}, at x = 100

d er i v a t i v e sin (e^{- 2 q})

\int (cos^{2} (2 x)) d x

\frac{\partial}{\partial y} (x^{2} y e^{x})