What is the integral of 15arctan(x) ?

The integral of 15arctan(x) is 15(xarctan(x)-1/2 ln|x^2+1|)+C

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integral of 15arctan(x)

\int 15 arctan (x) d x

15 (x arctan (x) - \frac{1}{2} ln x^{2} + 1) + C

Solution steps

\int 15 arctan (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 15 \cdot \int arctan (x) d x

Apply Integration By Parts

: x arctan (x) - \int \frac{x}{x ^{2} + 1} d x

= 15 (x arctan (x) - \int \frac{x}{x ^{2} + 1} d x)

\int \frac{x}{x ^{2} + 1} d x = \frac{1}{2} ln x^{2} + 1

= 15 (x arctan (x) - \frac{1}{2} ln x^{2} + 1)

Add a constant to the solution

= 15 (x arctan (x) - \frac{1}{2} ln x^{2} + 1) + C

\int \frac{ln ( x ^{14} )}{x} d x

\frac{\partial}{\partial x} (- y^{3} - x)

\int sin^{3} (\frac{x}{2}) cos (\frac{x}{2}) d x

\frac{e ^{- 3 s}}{s ^{2} + 6 s + 13}

f (x) = 13

What is the integral of 15arctan(x) ?
The integral of 15arctan(x) is 15(xarctan(x)-1/2 ln|x^2+1|)+C