derivative of xe^x-x

Lösung

\frac{d}{d x} (x e^{x} - x)

e^{x} + e^{x} x - 1

Schritte zur Lösung

\frac{d}{d x} (x e^{x} - x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x e^{x}) - \frac{d x}{d x}

\frac{d}{d x} (x e^{x}) = e^{x} + e^{x} x

\frac{d x}{d x} = 1

= e^{x} + e^{x} x - 1

ma c l a u r in (3 + x^{2})^{- 1}

n = 0 \sum \infty e^{(- 2 n)}

x \to 0 lim (2^{- \frac{1}{x ^{2}}})

\frac{\partial}{\partial x} (x y + yz + z x)

\frac{\partial}{\partial y} (x^{2} y - x y^{2})