tangent f(x)=(1-x)(x^2-3)2,(2,-1)

Lösung

tangente von

f (x) = (1 - x) (x^{2} - 3) 2, (2, - 1)

y = 2.90330 \dots x - 6.80661 \dots or y = - 3.89002 \dots x + 6.78004 \dots or y = - 16.51328 \dots x + 32.02656 \dots

Schritte zur Lösung

Steigung der Tangente an

(2, - 1) : m = \frac{- 2 x ^{3} + 2 x ^{2} + 6 x - 5}{x - 2}

Finde die Steigung von

f (x) = (1 - x) (x^{2} - 3) 2 : m = 2 (- 3 x^{2} + 2 x + 3)

Löse

2 (- 3 x^{2} + 2 x + 3) = \frac{- 2 x ^{3} + 2 x ^{2} + 6 x - 5}{x - 2} : x \approx - 0.45864 \dots, x \approx 1.65977 \dots, x \approx 2.29886 \dots

Finde die Tangente an

x = - 0.45864 \dots : y = 2.90330 \dots x - 6.80661 \dots

Finde die Tangente an

x = 1.65977 \dots : y = - 3.89002 \dots x + 6.78004 \dots

Finde die Tangente an

x = 2.29886 \dots : y = - 16.51328 \dots x + 32.02656 \dots

y = 2.90330 \dots x - 6.80661 \dots or y = - 3.89002 \dots x + 6.78004 \dots or y = - 16.51328 \dots x + 32.02656 \dots

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