integral of x^2+x-2

Lösung

\int x^{2} + x - 2 d x

\frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + C

Schritte zur Lösung

\int x^{2} + x - 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int x^{2} d x + \int x d x - \int 2 d x

\int x^{2} d x = \frac{x ^{3}}{3}

\int x d x = \frac{x ^{2}}{2}

\int 2 d x = 2 x

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x

Füge eine Konstante zur Lösung hinzu

= \frac{x ^{3}}{3} + \frac{x ^{2}}{2} - 2 x + C

d er i v a t i v e y = e^{\frac{1}{x}}

n = 0 \sum \infty n! \cdot x^{n}

d er i v a t i v e f (x) = tan (x) cot (x) sin (x)

\frac{d ^{2}}{d x ^{2}} (\frac{1 - 2 x}{1 + 2 x})

\int_{2}^{6} 1 + \frac{1}{4} x^{1} d x