y^{''}+20y^'+200y=150

Lösung

y^{^{''}} + 20 y^{^{'}} + 200 y = 150

y = e^{- 10 t} (c_{1} cos (10 t) + c_{2} sin (10 t)) + \frac{3}{4}

Schritte zur Lösung

y^{''} (t) + 20 y^{'} (t) + 200 y = 150

Solve linear ODE:

y = e^{- 10 t} (c_{1} cos (10 t) + c_{2} sin (10 t)) + \frac{3}{4}

y = e^{- 10 t} (c_{1} cos (10 t) + c_{2} sin (10 t)) + \frac{3}{4}

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