integral of 4/((1+x^2))

Lösung

\int \frac{4}{( 1 + x ^{2} )} d x

4 arctan (x) + C

Schritte zur Lösung

\int \frac{4}{1 + x ^{2}} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int \frac{1}{1 + x ^{2}} d x

Nutze das gemeinsame Integral :

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 4 arctan (x)

Füge eine Konstante zur Lösung hinzu

= 4 arctan (x) + C

t an g e n t f (x) = (x - 3)^{2} - 2, at x = 0

\frac{1}{x} y^{^{'}} = \frac{y}{x ^{2}} - \frac{1}{y}

\frac{\partial}{\partial y} (y^{3} + x^{2} y - 3 y)

n = 1 \sum \infty \frac{1}{n ln ( n )}

\int \frac{cos ( θ )}{9 - sin ^{2} ( θ )} d θ