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Popular >

integral from 0 to 1 of (x+y)

Solution

\int_{0}^{1} (x + y) d x

Solution

y + \frac{1}{2}

Solution steps

\int_{0}^{1} x + y d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} y d x + \int_{0}^{1} x d x

\int_{0}^{1} y d x = y

\int_{0}^{1} x d x = \frac{1}{2}

= y + \frac{1}{2}

Popular Examples

integral of (e^tsqrt(e^t+2))/(e^t+6)

\int \frac{e ^{t} e ^{t} + 2}{e ^{t} + 6} d t

y^{''}-1y^'-12y=0

y^{^{''}} - 1 y^{^{'}} - 12 y = 0

(\partial)/(\partial x)(xy-y+sin(1))

\frac{\partial}{\partial x} (x y - y + sin (1))

integral from 0 to 2 of 2^{-θ}

\int_{0}^{2} 2^{- θ} d θ

integral of sin^3(4x)sqrt(cos(4x))

\int sin^{3} (4 x) cos (4 x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of (x+y) ?
The integral from 0 to 1 of (x+y) is y+1/2