derivative sqrt(2t^2-t)

Lösung

ableitung von

2 t^{2} - t

\frac{4 t - 1}{2 2 t ^{2} - t}

Schritte zur Lösung

\frac{d}{d t} (2 t^{2} - t)

Wende die Kettenregel an:

\frac{1}{2 2 t ^{2} - t} \frac{d}{d t} (2 t^{2} - t)

= \frac{1}{2 2 t ^{2} - t} \frac{d}{d t} (2 t^{2} - t)

\frac{d}{d t} (2 t^{2} - t) = 4 t - 1

= \frac{1}{2 2 t ^{2} - t} (4 t - 1)

Vereinfache

\frac{1}{2 2 t ^{2} - t} (4 t - 1) : \frac{4 t - 1}{2 2 t ^{2} - t}

= \frac{4 t - 1}{2 2 t ^{2} - t}

\frac{d}{d x} (x - in x)

l a pl a ce t r an s f or m t e^{- 0.003 t} cos (10 t)

\int_{0}^{1} \frac{1}{( x + 1 ) ( x ^{2} + 1 )} d x

t an g e n t f (x) = x^{4} + 8 x^{3} + 2 x + 2, at x = 1

\frac{\partial}{\partial x} (\frac{12 x}{x + y})