What is (\partial)/(\partial y)(3x^4y^2+1) ?

The answer to (\partial)/(\partial y)(3x^4y^2+1) is 6x^4y

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(\partial)/(\partial y)(3x^4y^2+1)

\frac{\partial}{\partial y} (3 x^{4} y^{2} + 1)

6 x^{4} y

Solution steps

\frac{\partial}{\partial y} (3 x^{4} y^{2} + 1)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{4} y^{2}) + \frac{\partial}{\partial y} (1)

\frac{\partial}{\partial y} (3 x^{4} y^{2}) = 6 x^{4} y

\frac{\partial}{\partial y} (1) = 0

= 6 x^{4} y + 0

Simplify

= 6 x^{4} y

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What is (\partial)/(\partial y)(3x^4y^2+1) ?
The answer to (\partial)/(\partial y)(3x^4y^2+1) is 6x^4y