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Popular >

area y=2x^2,y=3-x

Solution

area

y = 2 x^{2}, y = 3 - x

Solution

\frac{125}{24}

+1

Decimal Notation

5.20833 \dots

Solution steps

Apply the area formula:

\int_{- \frac{3}{2}}^{1} 2 x^{2} - (3 - x) d x

Solve

\int_{- \frac{3}{2}}^{1} 2 x^{2} - (3 - x) d x : \frac{125}{24}

The area is:

= \frac{125}{24}

Popular Examples

integral of (5x^2+2/(x^4)-3\sqrt[3]{x})

limit as x approaches 5 of (4x)/(x-5)

x \to 5 lim (\frac{4 x}{x - 5})

y^'=(t+y)^2-1,y(3)=6

y^{^{'}} = (t + y)^{2} - 1, y (3) = 6

integral of ((x^2+3x-4))/(x^3-4x^2+4x)

\int \frac{( x ^{2} + 3 x - 4 )}{x ^{3} - 4 x ^{2} + 4 x} d x

area y=4x^2,x=1,y=0 area

y = 4 x^{2}, x = 1, y = 0

Frequently Asked Questions (FAQ)

What is area y=2x^2,y=3-x ?
The answer to area y=2x^2,y=3-x is 125/24