inverselaplace f(s)=s-3(s^2+4s+13)

Lösung

inverse laplace transformation

f (s) = s - 3 (s^{2} + 4 s + 13)

No solution in terms of standard functions

Schritte zur Lösung

L^{- 1} {s - 3 (s^{2} + 4 s + 13)}

= No solution in terms of standard functions

a re a y^{2} = 4 x, y^{2} = \frac{4}{x}

n = 1 \sum \infty \frac{( 2 n ) !}{5 ^{n} ( n ! ) ^{2}}

x \to 0 lim (\frac{e ^{x^{5}} - 1}{x})

\int_{2}^{r} \frac{1}{x ln ( x )} d x

\int \frac{e ^{x}}{( 4 - e ^{x} ) ^{2}} d x