derivative f(x)=x^3-3x+1

Lösung

ableitung von

f (x) = x^{3} - 3 x + 1

3 x^{2} - 3

Schritte zur Lösung

\frac{d}{d x} (x^{3} - 3 x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (1) = 0

= 3 x^{2} - 3 + 0

Vereinfache

= 3 x^{2} - 3

a re a x = 36 - y^{2}, x = y^{2} - 36

\int t - cos (t) d t

\frac{d}{d x} (\frac{3 x ^{2} - 18 x + 25}{x ^{2} - 6 x + 8})

\int \frac{4 x - 2}{( 4 x ^{2} - 4 x + 2 ) ^{4}} d x

in v erse l a pl a ce \frac{1 - e ^{- 2 s}}{6 s ^{2}}